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The osmotic pressure of blood is 8.21 atm at 300 K. An aqueous solution of glucose which is isotonic with blood has the percentage (wt./vol) strength of

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4 %

3 %

9 %

6 %

answer is A.

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Detailed Solution

$π = C R T$ $C = \frac{π}{R T}$
$\frac{% W / V \times 10}{G M W_{s o l u t e}} = \frac{π}{R T}$
$% W / V = \frac{8.21 \times 180}{10 \times 0.0821 \times 300} = 6 %$

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