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The outer electronic configuration of Ag is 4d ¹⁰ 5s¹, it belongs to

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4^th period, group 5

6^th period, group 9

5^th period, group 4

5^th period, group 11

answer is C.

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Detailed Solution

d-block - (n-1)d^1-10 ns^1-2

Ag -d-block elements

G.No.=no. of electrons (n-1)shell +no. of electrons in n^th shell

=10+1=11

period no. = Principal quantum number of valence shell

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