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Q.

The outer electronic configuration of cerium (Z = 58) is

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a

(4d)10(5s)2(5p)6(4f)3(6s)1

b

(4d)10(5s)2(5p)6(5d)3(6s)2

c

(4d)10(5s)2(5p)6(4f)2(5d)0(6s)2

d

(5d)10(5s)2(5p)6(5d)1(6s)2

answer is D.

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Detailed Solution

The expected outer electronic configuration of  58Ce is (4f)1(5d)1(6s)2. But due to very similar energies of 4f and 5d orbitals in all the lanthanides excepting Gd 4f75d16s2 and  71Lu4f14,5d1,6s2,(5d)1electron is shifted to (4f) orbital and hence 5d orbital remains unoccupied. Thus, the observed configuration of  58Ce is (4f)2(5d)0(6s)2.

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