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The outermost electronic configuration of most electropositive element is

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${ns}^{2} {npp}^{3}$

${ns}^{1}$

${ns}^{2} {np}^{5}$

${ns}^{2} n p^{2}$

answer is A.

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Detailed Solution

We know that for an element to be more electropositive the ionisation energy should be less so that it is easy to remove electron from that.

And, ionisation energy increases as we move along a period.

So, ${ns}^{1}$ would have least ionisation energy .

Therefore, it is more electropositive.

Hence, option(a) is the answer.

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