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The oxidation number of hydrogen in CaH₂ and NaH are respectively

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+ 1 and + 1

– 2 and – 1

– 1 and – 1

+ 1 and – 2

answer is A.

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Detailed Solution

The oxidation number of hydrogen in CaH₂ and NaH are:

$For {CaH}_{2}, Oxidation state of C + 2 (oxidation state of H) = 0 2 + 2 (oxidation state of H) = 0 oxidation state of H = - 1 For NaH, Oxidation state of Na + oxidation state of H = 0 1 + oxidation state of H = 0 oxidation state of H = - 1$

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