Q.

The oxidation number of  in S2O82- is:

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answer is 6.

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Detailed Solution

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If O.N. of S in S2O82- is x then:

2(x)+8(-2)=-2 x=+7 but O. N. of S can not exceed +6.

This means that there is peroxide linkage in the S2O82-, its structure is:

Question Image

Oxidation state of S in S2O82-

2x+6-2+2-1=-2 2x-12-2=-2 x=+6

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The oxidation number of  in S2O82- is: