The oxidation number of ‘Mn’ in ${\mathrm{KMnO}}_4 \mathrm{is}$

In ${\mathrm{KMnO}}_4,$ there is one potassium atom, 1 manganese atom and 4 oxygen atoms are present. The oxidation number of Mn in  ${\mathrm{KMnO}}_4,$ is calculated as below:

${\mathrm{KMnO}}_4,\Rightarrow 1\left(\mathrm{k}\right)+1\left(\mathrm{Mn}\right)+4\left(\mathrm{O}\right)=0$

$1(+1)+1\left(\mathrm{x}\right)+4(-2)=0$

x=8-1

x=+7 

Here x is oxidation number of Mn

Oxidation number of ‘Mn’ in ${\mathrm{KMnO}}_4 \mathrm{is} +7$