The oxidation number of ‘Mn’ in ${\mathrm{KMnO}}_4 \mathrm{is}$

The compound KMnO₄ (Potassium Permanganate) contains:

• 1 Potassium atom (K)
• 1 Manganese atom (Mn)
• 4 Oxygen atoms (O)

To determine the oxidation number of Mn in KMnO₄, we use the following steps:

Step-by-Step Calculation:

1. Oxidation Numbers of Known Elements:
   • Potassium (K) is in Group 1, so its oxidation number is +1.
   • Oxygen (O) generally has an oxidation number of -2 (except in peroxides or superoxides).
2. Total Charge of KMnO₄: KMnO₄ is a neutral compound, so the sum of oxidation numbers of all its atoms is 0.

3. Let the Oxidation Number of Mn be x: The total oxidation number equation is:

   (Oxidation number of K) + (Oxidation number of Mn) + (Oxidation number of O × Number of O atoms) = 0

   Substituting the values:

   (+1) + x + (-2 × 4) = 0

4. Simplify the Equation:

   1 + x - 8 = 0

   x = 8 - 1

   x = +7

Final Answer:

The oxidation number of Mn in KMnO₄ is +7.

Explanation with Keyword Usage:

In KMnO₄, the kmno4 oxidation number of manganese (Mn) is calculated using the rules of oxidation numbers and the neutrality of the compound. Potassium contributes +1, and each oxygen contributes -2. Solving for manganese gives an oxidation number of +7, which indicates that Mn in KMnO₄ is in a highly oxidized state.

The kmno4 oxidation number concept is essential for understanding redox reactions, where KMnO₄ often acts as a strong oxidizing agent due to Mn's high oxidation state of +7. Thus, identifying the kmno4 oxidation number helps in predicting its chemical behavior in reactions.