The oxidation number of ‘N’ in ${\mathrm{N}}_2{\mathrm{O}}_5 \mathrm{is}$

In ${\mathrm{N}}_2{\mathrm{O}}_5$ the oxidation number of “O” is −2 . So, the oxidation number of ‘N’ can be calculated as follows

${\mathrm{N}}_2{\mathrm{O}}_5\Rightarrow 2\times \left(\mathrm{x}\right)+5(-2)=0$

Then x =+5

Therefore, the oxidation number of nitrogen in ${\mathrm{N}}_2{\mathrm{O}}_5 \mathrm{is} +5$