The oxidation number of oxygen in $O_{2} F_{2}$ and ${OF}_{2}$ are

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$- 1, - 2$

$- 2, + 1$

$+ 2, + 1$

$+ 1, + 2$

answer is C.

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Detailed Solution

In oxy fluorides, the oxidation state of fluorine (F) is negative $(- 1)$ only.

The oxidation state of oxygen is positive. This is due to electronegative difference between O and F. The electro negativity (E.N) of F is 4.0 where as E.N of oxygen (O) is 3.5.

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