The oxidation number of sulphur in S₈ , S₂ F₂ and H2S respectively are :

Sulphur exists in elemental form so it has zero oxidation state. As a result oxidation number of Sulphur.

Oxidation number of Sulphur in ${\mathrm{S}}_2{\mathrm{F}}_2$ is $+1$ as oxidation number of F is $-1$.
Oxidation number of Sulphur in ${\mathrm{H}}_2\mathrm{S}$ is $-2$ as oxidation number of hydrogens is $+1$

Hence correct option is A