The oxidation number of sulphur in S8, S2F2 and H2S are

S8: ox. state of 'S' =0 S2F2 : 2x+2(-1)=0⇒x=+1 H2S : 2(+1)+x=0 ⇒x=-2

The oxidation number of sulphur in S8, S2F2 and H2S are

S8: ox. state of 'S' =0 S2F2 : 2x+2(-1)=0⇒x=+1 H2S : 2(+1)+x=0 ⇒x=-2

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The oxidation number of sulphur in S₈, S₂F₂ and H₂S are

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0, + 1 and - 2

+2, +1 and - 2

0, +1 and + 2

-2, + 1 and - 2

answer is A.

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Detailed Solution

$S_{8} : ox . state of' S' = 0 S_{2} F_{2} : 2 x + 2 (- 1) = 0 \Rightarrow x = + 1 H_{2} S : 2 (+ 1) + x = 0 \Rightarrow x = - 2$

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The oxidation number of sulphur in S8, S2F2 and H2S are

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The oxidation number of sulphur in S₈, S₂F₂ and H₂S are