The oxidation numbers of oxygen atoms in hydrogen peroxide, respectively, are

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$-$ 1 and $-$ 1

$-$ 2 and $-$ 2

$-$ 1 and $-$ 2

0 and O

answer is B.

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Detailed Solution

The chemical name for hydrogen peroxide is $H_{2} O_{2}$
H has an oxidation number of 1, but when mixed with fewer electronegative elements, it becomes negative.
Since oxygen has a greater electronegative charge than hydrogen, the amount of hydrogen that is oxidised in $H_{2} O_{2}$ be X.
Let the amount of oxygen for oxidation in.
As a result, the total number of oxidations for all the atoms in a neutral chemical is zero.

$\begin{array}{l} ∴ (x \times 2) + ((+ 1) \times 2) = 0 \\ \Rightarrow 2 x + 2 = 0 \\ \Rightarrow x = - 1 \end{array}$