The oxidation number(s) of sulphur in pyrosulphurous acid $(H_{2} S_{2} O_{5})$ is/are

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$+ 5, + 3$

$+ 4, + 2$

$+ 6, + 6$

$+ 5, + 5$

answer is C.

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Detailed Solution

The structure of $H_{2} S_{2} O_{5}$ is

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The oxidation number of Sulphur atoms are +5 and +3, respectively.

In pyrosulphurous acid ( $\text{H}_2\text{S}_2\text{O}_5$ $H$ $2$ $$ $S$ $2$ $$ $O$ $5$ $$ ), sulfur atoms have oxidation numbers of +5 and +3 due to their different bonding environments. The molecule contains two sulfur atoms: one is bonded to three oxygen atoms, which gives it an oxidation number of +5, and the other is bonded to one oxygen atom and another sulfur atom, resulting in an oxidation number of +3. The sum of the oxidation states of the two sulfur atoms is +8, which matches the overall neutral charge of the molecule. Therefore, the oxidation states of sulfur in this compound are +5 and +3.