The oxidation numbers of $Mn$ in $K_{2} {MnO}_{4}$ and $K_{3} [Mn (CN)_{6}]$ are respectively.

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$+ 6$ and $+ 2$

$+ 7$ and $+ 2$

$+ 7$ and $+ 6$

$+ 6$ and $+ 3$

answer is A.

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Detailed Solution

Let us assume oxidation numbers of $Mn$ in $K_{2} {MnO}_{4}$ is $X$

Oxidation number of potassium and oxygen are $+ 1$ and $- 2$ respectively $2 (1) + X + 4 (- 2) = 0$

$2 + X - 8 = 0$

$X - 6 = 0; X = + 6$ ,

Let us assume oxidation numbers of $Mn$ in $K_{3} [Mn (CN)_{6}]$ is $X$

Oxidation number of potassium and cyanide are $+ 1$ and $- 1$ respectively $3 (1) + x + 6 (- 1) = 0$

$3 + x - 6 = 0$

$X - 3 = 0; X = + 3$ , The oxidation numbers of $Mn$ in $K_{3} [Mn (CN)_{6}]$ is $+ 3$

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