The oxidation potentials of following half-cell reactions are given $\mathrm{Zn}\to {\mathrm{Zn}}^{2+}+2{\mathrm{e}}^{-};{\mathrm{E}}^{\mathrm{o}}=+0.76\mathrm{V}, \mathrm{Fe}\to {\mathrm{Fe}}^{2+}+2{\mathrm{e}}^{-};{\mathrm{E}}^{\mathrm{o}}=0.44\mathrm{V}$ what will be the emf of cell, whose cell-reaction is ${\mathrm{Fe}}^{2+}\left(\mathrm{aq}\right)+\mathrm{Zn}\to {\mathrm{Zn}}^{2+}\left(\mathrm{aq}\right)+\mathrm{Fe}$