The oxidation potentials of Zn,Cu, Ag, $H_{2}$ and Ni are 0.76, -0.34, -0.80, 0.00, 0.25 volt, respectively. Which of the following reactions will provide maximum voltage?

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$Zn + 2 {Ag}^{+} \to 2 Ag + {Zn}^{2 +}$

$H_{2} + {Ni}^{2 +} \to 2 H^{+} + Ni$

$H_{2} + {Cu}^{2 +} \to 2 H^{+} + Cu$

$Zn + {Cu}^{2 +} \to Cu + {Zn}^{2 +}$

answer is B.

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Detailed Solution

$E_{cell}^{o} = 0 .8 - (- 0 .76) = 1 .56 V$

Maximum voltage is produced when electrode having minimum oxidation potential is made cathode and maximum oxidation potential is made anode.

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