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Q.

The oxidation state of Fe in brown ring complex FeH2O5NOSO4 is

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a

+3

b

+4

c

+2

d

+1

answer is A.

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Detailed Solution

The oxidation state of Fe in the brown ring complex[Fe(H2O)5NO]SO4 is a common query in coordination chemistry. The "brown ring complex" forms during chemical tests for nitrates. Understanding its oxidation states involves calculating the contributions of all components within the complex.

Here’s the step-by-step explanation:

  1. The brown ring complex is written as [Fe(H2O)5NO]2+ SO42−. The coordination sphere [Fe(H2O)5NO]2+ carries an overall charge of +2.
  2. The oxidation state of each component in the coordination sphere must add up to the overall charge of +2.
  3. In the coordination sphere:
    • Water (H2O) is neutral and does not affect the oxidation state.
    • Nitrosyl (NO) in this complex has an oxidation state of +1.
    • Let the oxidation state of Fe be x.
  4. Writing the equation for the oxidation states:

x + (5 × 0) + (+1) = +2

Simplify:

x + 1 = 2

Solve for x:

x = +1

Thus, the oxidation state of Fe in the brown ring complex is +1.

 

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