The oxidation state of Fe in brown ring complex FeH₂O₅NOSO₄ is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The oxidation state of Fe in the brown ring complex[Fe(H₂O)₅NO]SO₄ is a common query in coordination chemistry. The "brown ring complex" forms during chemical tests for nitrates. Understanding its oxidation states involves calculating the contributions of all components within the complex.

Here’s the step-by-step explanation:

The brown ring complex is written as [Fe(H₂O)₅NO]²⁺ SO₄²⁻. The coordination sphere [Fe(H₂O)₅NO]²⁺ carries an overall charge of +2.
The oxidation state of each component in the coordination sphere must add up to the overall charge of +2.
In the coordination sphere:
- Water (H₂O) is neutral and does not affect the oxidation state.
- Nitrosyl (NO) in this complex has an oxidation state of +1.
- Let the oxidation state of Fe be x.
Writing the equation for the oxidation states: