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The oxidation state of iron in Na₄[Fe(CN)₅(NOS)] is :

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zero

answer is B.

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Detailed Solution

The compound given is: Na₄[Fe(CN)₅(NOS)],

Let, oxidation number of Fe=x

Oxidation number of CN=−1

Oxidation number of NOS=−1

Therefore, x+(−1)×5+1(−1)=−4

x−5−1=−4

x=+2

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