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Q.

The oxidation state of nitrogen in $N_{3} H$ is

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a

+ 3

b

$+ \frac{1}{3}$

c

$- 1$

d

$- \frac{1}{3}$

answer is D.

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Detailed Solution

In hydrazoic acid $(N_{3} H)$ nitrogen shows $- \frac{1}{3}$ oxidation state.

${\overset{*}{N}}_{3} H$

$3 x + 1 = 0, 3 x = - 1, x = - \frac{1}{3}$

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