The oxidation states of sulphur in the anions ${SO}_{3}^{2 -}$ , $S_{2} O_{4}^{2 -}$ and $S_{2} O_{6}^{2 -}$ follow the order :

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$S_{2} O_{6}^{2 -} < S_{2} O_{4}^{2 -} < {SO}_{3}^{2 -}$

$S_{2} O_{4}^{2 -} < {SO}_{3}^{2 -} < S_{2} O_{6}^{2 -}$

$S_{2} O_{4}^{2 -} < S_{2} O_{6}^{2 -} < {SO}_{3}^{2 -}$

${SO}_{3}^{2 -} < S_{2} O_{4}^{2 -} < S_{2} O_{6}^{2 -}$

answer is B.

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Detailed Solution

The oxidation states of Sulphur in the anions $S_{2} O_{4}^{2 -}$ and $S_{2} O_{6}^{2 -}$ follow the order:

$S_{2} O_{4}^{2 -} < {SO}_{3}^{2 -} < S_{2} O_{6}^{2 -}$ .

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