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The oxidation states of the most electronegative element in the products of the reaction between ${B a O}_{2}$ and dilute $H_{2} {S O}_{4}$ are

Moderate

A

0 and $- 1$

B

$- 1$ and $- 2$

C

$- 2$ and 0

D

$- 2$ and $+ 1$

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