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The oxidation states of the most electronegative element in the products of the reaction between BaO2 and dilute H2SO4 are

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a
0 and -1
b
-1 and -2
c
-2 and 0
d
-2 and +1

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detailed solution

Correct option is B

The reaction between BaO2 and dilute H2SO4 is as follows:

BaO2+H2SO4BaSO4+H2O2

From the above reaction it is clear that the most electronegative element in the product is oxygen.

The oxidation state of oxygen in BaSO4 is -2 and in H2O2 is -1.

Hence the correct option is (B).

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