The P-V diagram of a cyclic process ABCA is as shown in the figure. Choose the correct statement

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$W_{CAB} = negative$

$Q_{A \to B} = negative$

$U_{B \to C} = positive$

$All of these$

answer is D.

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Detailed Solution

During process A to B, pressure and volume both are decreasing. Therefore, temperature and, hence, internal energy of the gas will decrease $(T \propto PV) or {ΔU}_{A \to B}$ negative. Further ${ΔW}_{A \to B}$ is also negative as the volume of the gas is decreasing. Thus, ${ΔQ}_{A \to B}$ is negative.

In process B to C, pressure of the gas is constant while volume is increasing. Hence, temperature should increase or ${ΔU}_{B \to C} =$ positive.

During C to A, volume is constant while pressure is increasing. Therefore, temperature and hence, internal energy of the gas should increase or ${ΔU}_{C \to A} =$ positive.

During process CAB, volume of the gas is decreasing. Hence, work done by the gas is negative.

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