The P-V diagram of a diatomic ideal gas system going under cyclic process as shown in figure. The magnitude of work done during an adiabatic process CD is ………….. (use, $\gamma =1.4$)

Given The final pressure of the adiabatic process,  ${\mathrm{p}}_1=200\mathrm{n}/{\mathrm{m}}^2$
The initial pressure of the adiabatic process ${\mathrm{p}}_1=100\mathrm{n}/{\mathrm{m}}^2$
The initial volume of the adiabatic process,  ${\mathrm{V}}_1=4{\mathrm{m}}^3$
The initial volume of the adiabatic process, ${\mathrm{V}}_1=3{\mathrm{m}}^3$
We know that for an adiabatic process 

$\begin{array}{l}\mathrm{W}=\frac{{\mathrm{p}}_{\mathrm{f}}{\mathrm{V}}_{\mathrm{f}}-{\mathrm{p}}_{\mathrm{i}}{\mathrm{V}}_{\mathrm{i}}}{1-\mathrm{\gamma }}\\ \mathrm{W}=\frac{200\left(3\right)-\left(100\right)\left(4\right)}{1-1.4}\\ \mathrm{W}=-500\mathrm{J}\end{array}$

So the work done by an adiabatic process is 500 J and negative sign represents the work done on the system.