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Q.

The P-V diagram of a system undergoing thermodynamic transformation is shown in figure. The work done on the system in going from A → B → C is 50 J and 20 cal heat is given to the system. The change in internal energy between A and C is:

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a

70 J

b

34 J

c

134 J

d

84 J

answer is D.

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Detailed Solution

Heat given ∆Q=20 cal =20×4.2=84 J.

Work done ∆W = – 50 J [As process is anticlockwise] 

By first law of thermodynamics

⇒  ∆U=∆Q-∆W=84--50=134 J

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