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Q.

The P-V diagram of diatomic ideal gas system going under cyclic process is shown in figure. The work done during an adiabatic process CD is $(u s e γ = 1.4)$

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a

200J

b

-500J

c

-400J

d

400J

answer is C.

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Detailed Solution

$P V^{γ} = constant$

Work done in Adiabatic process

$\Rightarrow W = \frac{1}{1 - γ} [P_{2} V_{2} - P_{1} V_{1}]$

$\Rightarrow W = \frac{1}{1 - 1.4} [200 \times 3 - 100 \times 4]$

$\Rightarrow W = - 500 J$

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