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Q.

The P-V diagram of diatomic ideal gas system going under cyclic process is shown in figure. The work done during an adiabatic process CD  is use   γ=1.4

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a

200J

b

-500J

c

-400J

d

400J

answer is C.

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Detailed Solution

PVγ= constant 

Work done in Adiabatic process

⇒W=11−γP2V2−P1V1

⇒W=11−1.4[200×3-100×4] 

⇒W=−500J

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