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The pair having the same magnetic moment is: (Atomic numbers: Cr= 24, Mn= 25, Fe= 26, Co= 27)

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${[Cr {(H_{2} O)}_{6}]}^{2 +}$ and ${[Fe {(H_{2} O)}_{6}]}^{2 +}$

${[Mn {(H_{2} O)}_{6}]}^{2 +}$ and ${[Cr {(H_{2} O)}_{6}]}^{2 +}$

${[Cr {(H_{2} O)}_{6}]}^{2 +}$ and ${[{CoCl}_{4}]}^{2 -}$

${[{CoCl}_{4}]}^{2 -}$ and ${[Fe {(H_{2} O)}_{6}]}^{2 +}$

answer is A.

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Detailed Solution

The central atoms in the given complexes have the following electronic configurations:

The complexes ${[Cr {(H_{2} O)}_{6}]}^{2 +}$ and ${[Fe {(H_{2} O)}_{6}]}^{2 +}$ have the same number of unpaired electrons in the central atom, and, hence these will have the same magnetic moment.

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