The pair of compounds that can not exist together is(i) FeCl3, SnCl2 (ii) HgCl2, SnCl2(iii) FeCl2, SnCl2 (iii) FeCl3, KI

(i) FeCl3 , SnCl2 Fe+3 + Sn+2 → Fe+2 +Sn+4Oxidant reductantbecause FeCl2 & SnCl2 react with each other they cannot exist together (ii) HgCl2, SnCl2 Hg+2 + Sn+2 → Hg+ + Sn+4oxidant reductantbecause HgCl2 & SnCl2 react with each other they cannot exist together (iii) FeCl2, SnCl2Fe+2 + Sn+2 → no reaction (iv) FeCl3 , KI Fe+3 + I- → Fe+2 + I2Oxidant reductant because Fe+3 & I- react with each other they cannot exist togethertherefore I,II,IV cannot exist

The pair of compounds that can not exist together is(i) FeCl3, SnCl2 (ii) HgCl2, SnCl2(iii) FeCl2, SnCl2 (iii) FeCl3, KI

(i) FeCl3 , SnCl2 Fe+3 + Sn+2 → Fe+2 +Sn+4Oxidant reductantbecause FeCl2 & SnCl2 react with each other they cannot exist together (ii) HgCl2, SnCl2 Hg+2 + Sn+2 → Hg+ + Sn+4oxidant reductantbecause HgCl2 & SnCl2 react with each other they cannot exist together (iii) FeCl2, SnCl2Fe+2 + Sn+2 → no reaction (iv) FeCl3 , KI Fe+3 + I- → Fe+2 + I2Oxidant reductant because Fe+3 & I- react with each other they cannot exist togethertherefore I,II,IV cannot exist

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The pair of compounds that can not exist together is
(i) FeCl₃, SnCl₂
(ii) HgCl₂, SnCl₂
(iii) FeCl₂, SnCl₂
(iii) FeCl₃, KI

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(i) (ii) and (iv) only

(iii) only

(i) only

(ii) and (iii) only

answer is C.

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Detailed Solution

(i) FeCl_{3 ,} SnCl₂
Fe⁺³ + Sn⁺² $\to$ Fe⁺² +Sn⁺⁴
Oxidant reductant
because FeCl₂ & SnCl₂ react with each other they cannot exist together

(ii) HgCl₂, SnCl₂
Hg⁺² + Sn⁺² $\to$ Hg⁺ + Sn⁺⁴

oxidant reductant

because HgCl₂ & SnCl₂react with each other they cannot exist together

(iii) FeCl₂, SnCl₂
Fe⁺² + Sn⁺² $\to$ no reaction

(iv) FeCl₃ , KI
Fe⁺³ + I^- $\to$ Fe⁺² + I₂
Oxidant reductant
because Fe⁺³ & I^- react with each other they cannot exist together
therefore I,II,IV cannot exist

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