The pair of lines $a^2{x}^2+2h\left(a+b\right)xy+b^2{y}^2=0anda{x}^2+2hxy+b{y}^2=0are$

Given Equation $a^2{x}^2+2h\left(a+b\right)xy+b^2{y}^2=0--\left(1\right)anda{x}^2+2hxy+b{y}^2=0--\left(2\right)$

Angle bisector of (1)

$\begin{array}{l}h\left(a+b\right)\left(x^2-y^2\right)=\left(a^2-b^2\right)xy\\ \Rightarrow h\left(a+b\right)\left(x^2-y^2\right)=\left(a-b\right)\left(a+b\right)xy\\ \Rightarrow h\left(x^2-y^2\right)=\left(a+b\right)xy\end{array}$

It represent angle bisector of (2)

The lines are equally inclined to each other