The pair of quantities having the same dimensions is

$\begin{array}{rl} & \left[\text{work}\right]={\mathrm{ML}}^2{\mathrm{T}}^{-2},\\ & \left[\text{Torque}\right]=[r\times F]={\mathrm{LMLT}}^{-2}={\mathrm{ML}}^2{\mathrm{T}}^{-2}\end{array}$

So, work and torque have same dimensional formula

$\text{(1) Impulse:}[\mathrm{F}\times \mathrm{t}]={\mathrm{MLT}}^{-2}\times \mathrm{T}={\mathrm{MLT}}^{-1}$

[Surface tension]  $=\frac{\left[\mathrm{F}\right]}{\left[\mathrm{L}\right]}=\frac{\left[{\mathrm{MLT}}^{-2}\right]}{\left[\mathrm{L}\right]}=\left[{\mathrm{MT}}^{-2}\right]$

(2) Angular momentum:

$\begin{array}{l}\left[\text{mor}\right]=ML{T}^{-1}\mathrm{L}={\mathrm{ML}}^2{\mathrm{T}}^{-1}\\ \left[\text{work}\right]=[\mathrm{F}.\mathrm{S}]={\mathrm{MLT}}^{-2}\mathrm{L}={\mathrm{ML}}^2{\mathrm{T}}^{-2}\end{array}$

(4) Young’s modulus:

$\left[\mathrm{Y}\right]=\frac{\left[\text{Stress}\right]}{\left[\text{Strain}\right]}=\left[\mathrm{F}\right]/\left[\mathrm{A}\right]=\frac{{\mathrm{MLT}}^{-2}}{{\mathrm{L}}^2}={\mathrm{ML}}^{-1}{\mathrm{T}}^{-2}$

$\left[\text{Energy}\right]=[\mathrm{F}.\mathrm{S}]={\mathrm{ML}}^2{\mathrm{T}}^{-2}$

So, work and torque have same dimensional formula.