The pair of species that has the same bond order in the following is

$$\begin{gathered} \mathrm{CO}=6+8=14\text{ electrons } \\ {\mathrm{NO}}^{+}=7+8-1=14\text{ electrons } \\ \text{ Both have electronic configuration : } \\ \mathrm{\sigma }1{\mathrm{s}}^2{\mathrm{\sigma }}^{*}1{\mathrm{s}}^2\mathrm{\sigma }2{\mathrm{s}}^2{\mathrm{\sigma }}^{*}2{\mathrm{s}}^2\mathrm{\sigma }2{\mathrm{p}}_{\mathrm{z}}^2\mathrm{\pi }2{\mathrm{p}}_{\mathrm{x}}^2\mathrm{\pi }2{\mathrm{p}}_{\mathrm{y}}^2 \\ \text{ So both have bond order }=\frac{10-4}{2}=3 \end{gathered}$$