The parameter $\frac{{\text{mQ}}^{\text{4}}}{{\epsilon }_0^2{\text{h}}^{\text{2}}}$ has the dimensions of (m = mass, Q = charge,${\in }_0=$  Permittivity and h =Planck’s constant)         

consider $\frac{{\text{MQ}}^4}{{\in }_0^2{\text{h}}^{\text{2}}}$

We have ${\in }_0=\frac{{\text{Q}}^{\text{2}}}{{\text{Fd}}^{\text{2}}}$

$\text{h}=\text{energy}\times \text{time}=\text{F}\times \text{d}\times \text{T}$, substituting ${\in }_0$

We get $\frac{{\text{MQ}}^4}{{\in }_0^2{\text{h}}^{\text{2}}}=$$\frac{{\text{MQ}}^{\text{4}}\times {\text{F}}^{\text{2}}{\text{d}}^{\text{4}}}{Q^4\times {\left(\text{F}\times \text{d}\times \text{T}\right)}^2}$

$=\frac{{\text{MQ}}^{\text{4}}\times {\text{F}}^{\text{2}}\times {\text{d}}^{\text{4}}}{Q^4\times {\text{F}}^2\times {\text{d}}^2\times {\text{T}}^2}$

$=\frac{{\text{Md}}^{\text{2}}}{{\text{T}}^{\text{2}}}\Rightarrow \frac{\text{kgm}}{{\text{s}}^{\text{2}}}\times \text{m}$ = work done