The partical moves along a straight line and its velocity at a distance 'x' from the origin is Ka2-x2. Then the acceleration of the particle is

v=ka2-x2 a=v1=k12a2-x2-2x.dxdt a=-kxa2-x2×v=-kxa2-x2ka2-x2 =-k2x

The partical moves along a straight line and its velocity at a distance 'x' from the origin is Ka2-x2. Then the acceleration of the particle is

v=ka2-x2 a=v1=k12a2-x2-2x.dxdt a=-kxa2-x2×v=-kxa2-x2ka2-x2 =-k2x

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The partical moves along a straight line and its velocity at a distance 'x' from the origin is $K \sqrt{a^{2} - x^{2} .}$ Then the acceleration of the particle is

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$- K^{2} x$

$- K^{2}$

answer is D.

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$v = k \sqrt{a^{2} - x^{2}} a = v^{1} = k \frac{1}{2 \sqrt{a^{2} - x^{2}}} (- 2 x) . \frac{dx}{dt} a = \frac{- kx}{\sqrt{a^{2} - x^{2}}} \times v = \frac{- kx}{\sqrt{a^{2} - x^{2}}} (k \sqrt{a^{2} - x^{2}}) = - k^{2} x$

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The partical moves along a straight line and its velocity at a distance 'x' from the origin is Ka2-x2. Then the acceleration of the particle is

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The partical moves along a straight line and its velocity at a distance 'x' from the origin is $K \sqrt{a^{2} - x^{2} .}$ Then the acceleration of the particle is