The passage of electricity through dil H2SO4 for 16 minutes liberates a total of 224 ml of H2. The strength of the current in amperes will be

96500 Coul liberates = 11200 ml at STP ? = 224 ml at STP=224×9650011200= 1930Amp×Sec = CoulombAmp×960=1930Amp = 2.01≃2A

The passage of electricity through dil H2SO4 for 16 minutes liberates a total of 224 ml of H2. The strength of the current in amperes will be

96500 Coul liberates = 11200 ml at STP ? = 224 ml at STP=224×9650011200= 1930Amp×Sec = CoulombAmp×960=1930Amp = 2.01≃2A

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The passage of electricity through dil H₂SO₄for 16 minutes liberates a total of 224 ml of H₂. The strength of the current in amperes will be

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96500 Coul liberates = 11200 ml at STP
? = 224 ml at STP

= $\frac{224 \times 96500}{11200}$ = 1930

Amp $\times$ Sec = Coulomb

Amp $\times$ 960=1930

Amp = 2.01 $≃$ 2A

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The passage of electricity through dil H2SO4 for 16 minutes liberates a total of 224 ml of H2. The strength of the current in amperes will be

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The passage of electricity through dil H₂SO₄for 16 minutes liberates a total of 224 ml of H₂. The strength of the current in amperes will be