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The path difference between two interfering waves at a point on the screen is $λ / 6$ from central maximum. The ratio of intensity at this point and that at the central fringe will be

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853

7.5

0.75

85.3

answer is A.

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Detailed Solution

$ϕ = \frac{2 π}{λ} (x)$

$ϕ = \frac{2 π}{λ} (\frac{λ}{6}) = \frac{π}{3}$

$∴ I = I_{c e n t r e} \cos^{2} ϕ / 2$

$\frac{I}{I_{c e n t r e}} = \cos^{2} ϕ / 2$

$= \cos^{2} 30^{\circ} = \frac{3}{4}$

=0.75

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