The peak emission from a black body at a certain temperature occurs at a wavelength of 6000 $A^0.$ On increasing its temperature, the total radiation emitted is increased to 16 times. These radiations are allowed to fall on a metal surface. Photoelectrons emitted by the peak radiation at higher temperature can be bought to rest by applying a potential equivalent to the excitation potential corresponding to the transition for the level n=4 to n=2 in the Bohr’s hydrogen atom. The work function of the metal is given by $\frac{\alpha }{100}eV$ where $\alpha$ is the numerical constant. The value of $\alpha$ is found out to be 53p find the value of ‘p’? [ Take: hc$=12420eV-\stackrel{\text{0}}{\text{A}}$ ]