The percentage by volume of ${\mathrm{C}}_3{\mathrm{H}}_8$ in a mixture of ${\mathrm{C}}_3{\mathrm{H}}_8$ , ${\mathrm{CH}}_4$and $\mathrm{CO}$ is $36.5$. Calculate the volume of ${\mathrm{CO}}_2$ produced when 100 mL of the mixture is burnt in excess of ${\mathrm{O}}_2$.

The percentage by volume of ${\mathrm{C}}_3{\mathrm{H}}_8$ in a mixture of ${\mathrm{C}}_3{\mathrm{H}}_8$ , ${\mathrm{CH}}_4$and $\mathrm{CO}$ is $36.5$. Calculate the volume of ${\mathrm{CO}}_2$ produced when 100 mL of the mixture is burnt in excess of ${\mathrm{O}}_2$.

$\begin{array}{cc}{\mathrm{C}}_3{\mathrm{H}}_8+5{\mathrm{O}}_2\to 3{\mathrm{CO}}_2+4{\mathrm{H}}_2\mathrm{O}& \\ 36.5& 3\times 36.5\end{array}$

$$\begin{gathered} {\mathrm{CH}}_4+2{\mathrm{O}}_2\to {\mathrm{CO}}_2+2{\mathrm{H}}_2\mathrm{O}; \mathrm{CO}+\frac{1}{2}{\mathrm{O}}_2\to {\mathrm{CO}}_2 \\ 100 - 36.5 \end{gathered}$$ 

Total ${\mathrm{CO}}_2$ produced= 100- 36.5 + 3 x 36.5 = 173 ml