The percentage of s-character in the orbital forming $\mathrm{P}-\mathrm{S}$ bonds in ${\mathrm{P}}_4{\mathrm{S}}_3$ is :

Due to ${\mathrm{sp}}^3$ hybridization, the orbital generating the $\mathrm{P}–\mathrm{S}$ bonds in ${\mathrm{P}}_4-{\mathrm{S}}_3$ contains 25% of the s-character.

$\mathrm{P}\to s{p}^3(\mathrm{\%}s=25\mathrm{\%})$

Correct option is A.