The perfect formula used for calculating induced e.m.f in a rod moving in a uniform magnetic field is (where terms have their usual meaning)

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$e = \vec{B} \times (\vec{l} . \vec{v})$

$e = \vec{B} . (\vec{l} . \vec{v})$

$e = \vec{B} \times (\vec{l} \times \vec{v})$

$e = \vec{B} . (\vec{l} \times \vec{v})$

answer is A.

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Detailed Solution

$i n d u c e d e m f i s a s c a l a r q u a n t i t y$

$h e n c e i t i s a s c a l a r t r i p l e p r o d u c t o f m a g n e t i c f i e l d s t r e n g t h (B), l e n g t h o f c o n d u c t o r (l) a n d v e l o c i t y o f c o n d u c t o r (v)$ $e = \vec{B} . (\vec{l} \times \vec{v})$

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