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Q.

The perimeter of an isosceles triangle is 42 cm and its base is 1 1 2    times, each of the equal sides. The area of the triangle is ____ c m 2  .


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Detailed Solution

The perimeter of an isosceles triangle is 42 cm and its base is 1 1 2    times, each of the equal sides. The area of the triangle is 71.43 c m 2  .
Given the perimeter of an isosceles triangle is 42 cm and its base is 1 1 2    times, each of the equal sides.
Let the length of 2 equal sides = x.
Therefore, the length of base is,  b=1 1 2 x   b= 3 2 x b=1.5xcm   Consider an isosceles triangle ABC with median AD,
ad is an altitude of an isos - Maths - TopperLearning.com | u261uh8nnNow the perimeter of triangle is,
perimeter=AB+BC+CA 42=x+1.5x+x 42=3.5x x=12cm   The length of equal sides = 12 cm,
The length of base = 18 cm,
As the median divides the side into two equal parts, so length of
BD=9cm
Calculating the height of median AD, using Pythagoras theorem,
hypotenuse 2 = base 2 + perpendicular 2   A B 2 =A D 2 +B D 2 12 2 =A D 2 + 9 2 A D 2 =14481 A D 2 =63 AD=3 7  
Now the area of triangle is,
A= 1 2 ×Base×Height A= 1 2 ×18×3 7 A=9×3 7 A=27 7  
Question ImageA = 71.43 c m 2   The area of the triangle is 71.43 c m 2  .
 
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The perimeter of an isosceles triangle is 42 cm and its base is 1 1 2    times, each of the equal sides. The area of the triangle is ____ c m 2  .