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Q.

The perimeter of the triangle whose vertices have the position vectors (i+j+k),(5i+3j3k) and (2i+5j+9k), is given by: 

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a

15+157

b

15157

c

15157

d

15+157

answer is A.

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Detailed Solution

a=4i+2j4k

 |a|=16+16+4=6 b=3i+2j+12k |b|=144+4+9=157 c=i4j8k |c|=64+16+1=9

Hence, perimeter is 15+157.

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