Q.

The perimeters of two similar triangles ∆ABC and ∆PQR are 35cm and 45cm respectively, then the ratio of the areas of the two triangles is


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a

49:81

b

50:81

c

41:81

d

49:89 

answer is A.

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Detailed Solution

Given that perimeters of two similar triangles ΔABC and ΔPQR  are 35 cm and 45 cm.
The perimeter of two similar triangles ABC and PQR class 9 maths CBSEWe know that, the ratio of perimeters of two similar triangles is equal to the ratio of their corresponding sides.
Here, ΔABC~ΔPQR  .
Then, AB PQ = BC QR = AC PR =  Perimeter of ΔABC  Perimeter of ΔPQR (1)  
Substitute given perimeter values of two similar triangles ΔABC and ΔPQR   in eq (1). AB PQ = BC QR = AC PR = 35 45 AB PQ = BC QR = AC PR = 7 9 (2)   Apply Area of similar triangles theorem i.e., the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
substitute the value from eq(2).
arΔABC arΔPQR = AB PQ 2 arΔABC arΔPQR = 7 9 2 arΔABC arΔPQR = 49 81   Hence, the ratio of the areas of the two triangles is 49: 81.
The correct option is (1).
 
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