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Q.

The period of a satellite in circular orbit of radius R is T. The period of an other satellite in a cicular orbit of radius 4R is

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a

T/8

b

T/4

c

4T

d

8T

answer is C.

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Detailed Solution

$\begin{array}{l} \frac{T_{2}}{T_{1}} = {[\frac{R_{2}}{R_{1}}]}^{3 / 2} \\ \frac{T_{2}}{T} = {[\frac{4 R}{R}]}^{3 / 2} \\ T_{2} = 8 T \end{array}$

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