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Q.

The period of a simple pendulum is found to increase by 50% when the length of the
pendulum is increased by 0.6m. Calculate the the period of oscillation at a place where g=9.8m/s2.

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answer is 1.39.

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Detailed Solution

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T=2πlg

given when l increases to l+0.6  

T becomes 3T2

32=l+0.6l

solving l=0.48m

substituting 

T=1.39 sec

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