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Q.

The period of $\cot (\frac{3 - 5 x}{7})$ is

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a

- \frac{7 π}{5}

b

\frac{14 π}{5}

c

\frac{7 π}{5}

d

\frac{5 π}{7}

answer is C.

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Detailed Solution

We have period of

\cot (a x + b)

is

\frac{π}{| a |}

$\cot (\frac{3 - 5 x}{7}) = \cot (\frac{- 5 x}{7} + \frac{3}{7})$

$∴$ Period of $\cot (\frac{- 5 x}{7} + \frac{3}{7}) = \frac{π}{| \frac{- 5}{7} |} = \frac{7 π}{5}$

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