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The period of revolution of a planet around the sun in a circular orbit is same as that of period of similar planet revolving around a star of twice the radius of first orbit and ‘M’ is the mass of the sun and mass of star is

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16M

answer is C.

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From Kepler’s 3rd law, ${mrw}^{2} = \frac{GMm}{r^{2}} T = 2 π \sqrt{\frac{r^{3}}{GM}}$

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