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Q.

The period of revolution of a surface satellite around a planet of radius R is T. The period of another satellite around the same planet in an orbit of radius 3R is

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a

3√3 T

b

T

c

3T

d

9T

answer is D.

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Detailed Solution

As we know $T \propto R^{3 / 2}$

$\frac{T_{1}}{T_{2}} = {(\frac{R}{3 R})}^{3 / 2} \Rightarrow T_{2} = T_{1} \times 3 \sqrt{3}$

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