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Q.

The period of revolution of an earth's satellite close to the surface of earth is 60 minutes. The period of another earth's satellite in an orbit at a distance of three times earth's radius from its surface will be (in minutes)

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a

270

b

480

c

90

d

90×8

answer is D.

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Detailed Solution

From Kepler’s 3rd law, T2∝r3

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