The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun

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answer is C.

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Detailed Solution

$\frac{T_{A}}{T_{B}} = {(\frac{r_{A}}{r_{B}})}^{3 / 2} \Rightarrow 8 = {(\frac{r_{A}}{r_{B}})}^{3 / 2} \Rightarrow r_{A} = (8)^{2 / 3} r_{B} = 4 r_{B}$

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