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Q.

The period of sin⁡4x+cos⁡4x is


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a

π 2

b

 π

c

 2π

d

none of these 

answer is A.

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Detailed Solution

Given function is,
fx=sin⁡4x+cos⁡4x
Since,
sin⁡n⋅360∘+θ=sin⁡θcos⁡n⋅360∘+θ=cos⁡θ
So,
fx=sin⁡2π+4x+cos⁡2π+4x
fx=sin⁡4x+π2+cos⁡4x+π2
So, the period of the given function is π2.
Correct option is 1.
 
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The period of sin⁡4x+cos⁡4x is